A steel block of 10kg rests on a horizontal floor as shown. When three iron cylinders are placed on it as shown, the block and cylinders go down with an acceleration 0.2m/s 2 . The normal reaction R’ by the floor if mass of the iron cylinders are equal and of 20kg each, is N. [Take 
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Text Solution
Verified by ExpertsThe correct answer is:
B
Writing force equation in vertical direction
Mg − N = Ma
70 g − N = 70 × 0.2
N = 70[ g − 0.2] = 70 × 9.8
N = 686 Newton
Note: Since there is no compressive normal from the sides, hence friction will not act.
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